Math, asked by aniy, 1 year ago

the average age of 8 man is decreased by 2 years when two of them whose ages are 22 and 28 are replaced by two boys what is the average age of the two boys


sanketwpatil123: incomplete details...just tell me the average......of all the 8 persons, before or after.

Answers

Answered by SARDARshubham
1

x1+x2+x3+x4+x5+x6+22+28/8 = m
x1+x2+x3+x4+x5+x6 = 8m - 50

let t be average age of two boys who has been replaced:
x1+x2+x3+x4+x5+x6 + t/8 = m-2
8m - 50 +t/8 = m-2
8m- 50+t = 8m -16
t= 50-16
t = 34

therefore the average age of two boys is 34 yrs.






SARDARshubham: mine answer is correct but it seems impossible to have the average age of boys 34 yrs, they should be called mens.
aniy: we have to divide 34 by 2 (34/2) which give 17.
SARDARshubham: no, average means the mean of both ages, that is 34 only
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