Math, asked by narutozosang3818, 1 year ago

The average age of three boys is 25 years and their ages are in the proportion 3 : 5 : 7. the age of the youngest boy is:

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Answered by hyunxu
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Answered by pulakmath007
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The age of the youngest boy = 15 years

Correct question : The average age of three boys is 25 years and their ages are in the ratio 3 : 5 : 7. the age of the youngest boy is:

Given :

The average age of three boys is 25 years and their ages are in the ratio 3 : 5 : 7

To find :

The age of the youngest boy

Solution :

Step 1 of 2 :

Form the equation to find the age of the youngest boy

Here it is given that the age of three boys are in the ratio 3 : 5 : 7

Let the ages of three boys are 3x years , 5x years , 7x years

Also it is given that the average age of three boys is 25 years

By the given condition

\displaystyle \sf   \frac{3x + 5x + 7x}{3}  = 25

Step 2 of 2 :

Find the age of the youngest boy

\displaystyle \sf   \frac{3x + 5x + 7x}{3}  = 25

\displaystyle \sf{ \implies } \frac{15x}{3}  = 25

\displaystyle \sf{ \implies }5x = 25

\displaystyle \sf{ \implies }x = 5

So the ages of three boys are 15 years , 25 years , 35 years

Hence age of the youngest boy = 15 years

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