Math, asked by Rajajhakas, 1 year ago

The average boys of 15 years. If their ages aur in the ratio 3:5:7 find the age of youngest boy. solve math

Anonymous: Sum of ages of three boys = 45 years
(3x+5x+7x) = 45
15x = 45
x = 3
So, age of youngest boy = 3x = 3*3 = 9 years.

Answers

Answered by desiboyz3

9, 15 , 21 year will be the answer

Attachments:

desiboyz3: sum= 3x + 6x + 12 x = 21x

desiboyz3: average = 21x /3 ,

desiboyz3: 42= 21x /3 ,21x = 42 × 3 = 126, x = 126/21= 6

desiboyz3: difference= 12x-3x= 9x = 9× 6 = 54 will be the answer

desiboyz3: plz mark

Rajajhakas: okk bro

desiboyz3: correct na?

Rajajhakas: nhi pata bro

desiboyz3: correct he , plz mark ,

desiboyz3: hello

Answered by Anonymous

Sum of ages of three boys = 45 years

(3x+5x+7x) = 45

15x = 45

x = 3

So, age of youngest boy = 3x = 3*3 = 9 years.

THANKS AND HOPE IT HELPS

-THEORIGINALS

Previous Question

Next Question