Math, asked by keerthanadileep02, 1 year ago

The average marks of A B and C is 33 and the average marks of B C and D is 37. If A obtains 30 marks, find the marks obtained by D.

Answers

Answered by pavani962003
50

(A+B+C)/3=33

(30+B+C)/3=33

30+B+C=99

B+C=69 ------------(1)

now,

(B+C+D)/3=37

(69+D)/3=37 [from (1)]

69+D=111

D=42

so, the marks obtained by D are 42.

Answered by qwmagpies
10

Given:

The average marks of A B and C is 33 and the average marks of B, C and D are 37. A obtains 30 marks.

To find:

We have to find the marks of D.

Solution:

The average marks of A B and C are 33.

So, we can write-

A+B+C/3=33

A+B+C=99

A obtains 30 marks.

30+B+C=99

B+C=69

Again the average marks of B, C and D are 37.

So, we can write-

B+C+D/3=37

B+C+D=111

69+D=111

D=111-69

D=42

The mark obtained by D is 42.

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