The average monthly income of 250 families in a certain barangay is Php25,500 with a standard deviation of Php3,200. Assuming that the family incomes are normally distributed, find the number of families who earn at most Php30,000 per month.
Answers
Given : The average monthly income of 250 families in a certain barangay is Php25,500 with a standard deviation of Php3,200.
family incomes are normally distributed,
To find : the number of families who earn at most Php30,000 per month.
Solution:
Z = ( Value - Mean)/SD
Value = 30000
Mean = 25500
SD = 3200
=> Z = (30000 - 25500)/3200
= 4500/3200
= 1.406
this z score refers to 0.928
Hence number of families who earn at most Php30,000 per month.
= 0.928 * 250
= 232
232 Families earns at most Php30,000 per month.
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