The average of three consecutive odd numbers is 14 more than one third of the first of these numbers .what is the last of these numbers 1)17 2)19 3)15 4)data inadequate
Answers
Answered by
5
We have 3 consecutive odd numbers
So they are in AP with d = 2
So, let the numbers be a - 2, a, a + 2
Average = (a - 2 + a + a + 2) / 3
= 3a /3 = a
So, we are given
Avg = 1/3 of first number + 14
So, a = 1/3 [ a - 2 ] + 14
a = a/3 - 2/3 + 14
2/3 a = 14 - 2/3
2/3 a = 42/3 - 2/3
2/3 a = 40/3
a = 20
So numbers are: 20 - 2, 20, 20 + 2
They are: 18, 20, 22
As the numbers are even numbers, answer is option D i.e. data inadequate
So they are in AP with d = 2
So, let the numbers be a - 2, a, a + 2
Average = (a - 2 + a + a + 2) / 3
= 3a /3 = a
So, we are given
Avg = 1/3 of first number + 14
So, a = 1/3 [ a - 2 ] + 14
a = a/3 - 2/3 + 14
2/3 a = 14 - 2/3
2/3 a = 42/3 - 2/3
2/3 a = 40/3
a = 20
So numbers are: 20 - 2, 20, 20 + 2
They are: 18, 20, 22
As the numbers are even numbers, answer is option D i.e. data inadequate
Answered by
2
Let the 3 consecutive odd numbers be x-2, x, x+2
Also, Average = 3x/3 = x
=> x = 14 + (x-2)/3 => 3x = 42 + x - 2 => 2x = 40=> x = 20
So, the numbers are Even but the required numbers should be odd
Thus the D option is correct
Also, Average = 3x/3 = x
=> x = 14 + (x-2)/3 => 3x = 42 + x - 2 => 2x = 40=> x = 20
So, the numbers are Even but the required numbers should be odd
Thus the D option is correct
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