Question

The avg of 8 numbers is 14 . Avg of 6 of these number is 16.The avg of remaining two numbers is.

Answer 1

Answer:

Let the numbers be a,b,c,d,e,f,g,h

Given that (a+b+c+d+e+f+g+h)/8 = 14

a+b+c+d+e+f+g+h = 112 -------(1)

Average of 6 numbers = 16

Hence let's exclude g & h

Now (a+b+c+d+e+f)/6 = 16

a+b+c+d+e+f = 96 --------------(2)

Substituting value from eq(2) in eq(1)

96+g+h = 112

g+h = 112-96

g+h = 16

Average of remaining g & h = (g+h)/2 =16/2 = 8

Answer 2

Answer:

8 is the average of the two numbers