Question

the bacteria in culture grows by 10% in the first hour , decreased by 10% in the second hour again increases by 10% the third hour , if the original count of a bacteria in a sample is 10000 find the bacteria count at the end of three hours.

Answer 1

Given bacteria count is 10000 at first hour it increases by 10% = 10000×10/100=1000 now bacteria count is 11000 at second hour it decreases by 10%=11000×10/100=1100 now bacteria count is 11000-1100 = again 10000 at third hour the count increases by 10%=10000×10/100=1000 now present bacteria count after three hours is 10000+1000 =11000

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Answer 2

Given bacteria count is 10000 at first hour it increases by 10% = 10000×10/100=1000 now bacteria count is 11000 at second hour it decreases by 10%=11000×10/100=1100 now bacteria count is 11000-1100 = again 10000 at third hour the count increases by 10%=10000×10/100=1000 now present bacteria count after three hours is 10000+1000 =11000