Question

The ball of mass 0.5kg is dropped some certain height as it falls through 2m the kinetic energy acquired by it is

Answer 1

K.E= 1/2mv^2

    =1/2*0.5*2^2

   = 1/2*0.5*4

   =2*0.5

K.E    =1J

Answer 2

The kinetic energy acquired by it is 9.79 J.

Explanation:

It is given that,

Mass of the ball, m = 0.5 kg

It falls through a distance of 2 meters, d = 2 m

Initially the ball is at rest, u = 0

Let v is the final speed of the ball. It can be calculated using third equation of motion as :

$v^2=u^2+2ad$

$v^2=2gd$

$v^2=2\times 9.8\times 2$

v = 6.26 m/s

Let K is the kinetic energy acquired by the ball. It is given by :

$K=\dfrac{1}{2}mv^2$

$K=\dfrac{1}{2}\times 0.5\times (6.26)^2$

K = 9.79 J

So, the kinetic energy acquired by it is 9.79 J.

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Work done

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