THE BASE AND HEIGHT OF A TRIANGLE IS IN THE RATIO 3:4 and its area is 96 cm ^2 find its base and height
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Answered by
9
let ratio be 3x and 4x
area=1/2×base×height
96=1/2×3x×4x
96=1/2×12x^2
192=12x^2
192÷12=x^2
16=x^2
4=x
so Base =3x=12
height=4x=16
area=1/2×base×height
96=1/2×3x×4x
96=1/2×12x^2
192=12x^2
192÷12=x^2
16=x^2
4=x
so Base =3x=12
height=4x=16
ahmad13:
wrong
Answered by
2
le the ratio be x
base=3x
height=4x
area of triangle =1/2×b×h
96m^2=1/2×3x×4x
96m^2=6x^2
x^2=16m^2
x=√16m^2
x=4m
base=3x=3×4m=12m
height=4x=4×4m=16m
hope this answer will help you
base=3x
height=4x
area of triangle =1/2×b×h
96m^2=1/2×3x×4x
96m^2=6x^2
x^2=16m^2
x=√16m^2
x=4m
base=3x=3×4m=12m
height=4x=4×4m=16m
hope this answer will help you
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