verify that 2,3 and 1/2 are the zeroes of the polynomial p (x)= 2x^3-11x^2+17x-6
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P(2)=2(2)^3-11(2)^2+17×2-6
=2×8-11×4+17×2-6
=16-44+34-6
=10-10
=0
P(3)=2×27-11×9+17×3-6
=54-99+51-6
=0
P(1/2)=2×1/8-11×1/4+17×1/2-6
=1/4-11/4+17/2-6/1
=(1-11+34-24)÷4
=(10-10)÷4
=0÷4
=0
Hence,2,3,1/2 are the zeroes of the polynomial2x^3-11x^2+17×1/2-6.
=2×8-11×4+17×2-6
=16-44+34-6
=10-10
=0
P(3)=2×27-11×9+17×3-6
=54-99+51-6
=0
P(1/2)=2×1/8-11×1/4+17×1/2-6
=1/4-11/4+17/2-6/1
=(1-11+34-24)÷4
=(10-10)÷4
=0÷4
=0
Hence,2,3,1/2 are the zeroes of the polynomial2x^3-11x^2+17×1/2-6.
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