The base of a right angled triangle is 12cm and its hypotenuse is 13cm. Find its area and perimeter .
Answers
Answered by
31
according to Pythagoras theorem,
the perpendicular will be 5 cm (whole root13^2- 12^2)
then area will be= 1/2* base* height=1/2*12*5=30cm^2
perimeter= 12+13+5=30 cm
the perpendicular will be 5 cm (whole root13^2- 12^2)
then area will be= 1/2* base* height=1/2*12*5=30cm^2
perimeter= 12+13+5=30 cm
Answered by
37
hey! here is your answer
base=12cm
hypotnuse=13cm
height=?
b^2+h^2=hypotnuse^2
12^2+h^2=13^2
144+h^2=169
h^2=169-144
h^2=25
h=5cm
area=1/2*b*h=1/2*12*5=6*5=30cm^2
perimeter=12+13+5=30cm
hope it helps!!
base=12cm
hypotnuse=13cm
height=?
b^2+h^2=hypotnuse^2
12^2+h^2=13^2
144+h^2=169
h^2=169-144
h^2=25
h=5cm
area=1/2*b*h=1/2*12*5=6*5=30cm^2
perimeter=12+13+5=30cm
hope it helps!!
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