Math, asked by muhannadsharji, 1 year ago

The base of a triangle is 9cm correct to the nearest cm
The are of this triangle is 40 cm² correct to the nearest 5 cm²
Calculate the upper bound for the perpendicular height of this triangle

Answers

Answered by abhi178
58
Area of triangle is 40 cm² correct to nearest 5cm² .
∴ Area of triangle = ( 40 ± 5) cm²
∴ upper bound for area of triangle is = (40 + 5) cm² = 45cm²
Base of triangle = 9cm

∵ area of triangle = 1/2 base × height
height = 2 × area of triangle/base

∴ upper bound for height of triangle = 2 × upper bound area/base
= 2 × 45/9 = 10cm

Hence answer is 10cm
Answered by tiwaavi
18
Hello Dear.

Here is the answer---

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Given Conditions,
 Base of the Triangles = 9 cm.

As per as the question,

   Area of the Triangle = (40 + 5) cm² 
                                     = 45 cm² 
       [Since we have to correct to 5 cm²]

Using the Formula,

    Area of the Triangle =  (1/2) × Base × Height
⇒ 45 = (1/2) × 9 × Height
⇒ Height = 90/9
⇒ Height =  10 cm
                                   

Thus, the Height of the Triangle, i.e. the Perpendicular Height of the Triangles is 10 cm.


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Hope it helps.

Have a Marvelous Day.
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