The base of a triangle is 9cm correct to the nearest cm
The are of this triangle is 40 cm² correct to the nearest 5 cm²
Calculate the upper bound for the perpendicular height of this triangle
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Answered by
58
Area of triangle is 40 cm² correct to nearest 5cm² .
∴ Area of triangle = ( 40 ± 5) cm²
∴ upper bound for area of triangle is = (40 + 5) cm² = 45cm²
Base of triangle = 9cm
∵ area of triangle = 1/2 base × height
height = 2 × area of triangle/base
∴ upper bound for height of triangle = 2 × upper bound area/base
= 2 × 45/9 = 10cm
Hence answer is 10cm
∴ Area of triangle = ( 40 ± 5) cm²
∴ upper bound for area of triangle is = (40 + 5) cm² = 45cm²
Base of triangle = 9cm
∵ area of triangle = 1/2 base × height
height = 2 × area of triangle/base
∴ upper bound for height of triangle = 2 × upper bound area/base
= 2 × 45/9 = 10cm
Hence answer is 10cm
Answered by
18
Hello Dear.
Here is the answer---
→→→→→→→→→
Given Conditions,
Base of the Triangles = 9 cm.
As per as the question,
Area of the Triangle = (40 + 5) cm²
= 45 cm²
[Since we have to correct to 5 cm²]
Using the Formula,
Area of the Triangle = (1/2) × Base × Height
⇒ 45 = (1/2) × 9 × Height
⇒ Height = 90/9
⇒ Height = 10 cm
Thus, the Height of the Triangle, i.e. the Perpendicular Height of the Triangles is 10 cm.
→→→→→→→→→→
Hope it helps.
Have a Marvelous Day.
Here is the answer---
→→→→→→→→→
Given Conditions,
Base of the Triangles = 9 cm.
As per as the question,
Area of the Triangle = (40 + 5) cm²
= 45 cm²
[Since we have to correct to 5 cm²]
Using the Formula,
Area of the Triangle = (1/2) × Base × Height
⇒ 45 = (1/2) × 9 × Height
⇒ Height = 90/9
⇒ Height = 10 cm
Thus, the Height of the Triangle, i.e. the Perpendicular Height of the Triangles is 10 cm.
→→→→→→→→→→
Hope it helps.
Have a Marvelous Day.
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