Question

The base of a triangular field 2 times its altitude.if its area is 400m square then its base is

Answer 1

Let altitude of triangular field be x , then its base = 2x.

Area of triangular field = 1/2 × base × altitude = 400
1/2× 2x × x = 400
2x sq. = 800
x sq. = 400
x = 20

Base of triangular field = 2x = 2×20 = 40 m

Answer 2

Answer:

The base of the triangular field = 40m

Step-by-step explanation:

Given,

The base of a triangular field is 2 times its altitude

Area of the field  = 400m²

To find,

The base of the triangular field.

Recall the formula

The area of a triangle = $\frac{1}{2}$×b×h, where 'b' is the base and 'h' is the height of the triangle.

Solution

Let 'b' be the base of the triangular field and 'h' is the altitude

Given that the base of a triangular field is 2 times its altitude

b = 2h

Since the area of the field =  400m²

$\frac{1}{2}$×b×h = 400

b×h = 800

2h×h = 800

h² = 400

h = $\sqrt{400}$ = 20m

Height of the triangular field = 20m

Base of the triangular field = 2×20 = 40m

∴Base of the triangular field = 40m

#SPJ3