The base of an isosceles triangle is 12 cm and its
nerimeter is 32 cm. Then its area is
Answers
Answer:
60 cm^2
Step-by-step explanation:
Perimeter of the triangle = 32cm
base of the triangle = 12cm
Then the other two sides are equal because it is an isosceles triangle
Now we have to find the other two sides
12 + X + X = 32
12 + 2x = 32
2x = 32-12
2x = 20
X = 10
So the other two sides are 10cm and 10cm.
Now the area of isosceles triangle is:- 1/2 × b × h
= 1/2 × 12 × 10
= 6 × 10
= 60 cm^2
Answer:
48 cm²
Step-by-step explanation:
length of base = 12 cm
perimeter=32 cm
since the triangle is an isosceles triangle, the remaining two sides are equal.
The length of the equal sides is given by,
12+2X = 32
2X=32-12
=20 cm
X=20/2
=10 cm
To find the area , we need to know the height of the triangle.
If we draw the height for the triangle as in the attachment, we get the length of the height by using the Pythagoras theorem.
AD ²+DC²=AC²
AC²-DC²=AD²
here, the value of DC is 1/2 of BC i.e 6 cm
100-36=AD²
AD²=64
AD=√64
=8 cm
The area of isosceles triangle is given by,
Δ=1/2×b×h
=1/2×12×8
=48 cm²
Therefore,the area is 48 cm²
hope it helped:)
