Question

the base of an isosceles triangle is 5/3 cm .if the permiter of the triangle is 43/6cm, find the lenght of the remaining equal sides

Answer 1

$<b><i><u>Hey mate!! Here's your answer</u></i></b>$
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$\huge{Given\: -}$

The base of an isosceles triangle is 5/3 cm and it's perimeter is 43/6 cm.

$\huge{To\: Find}$

The length of other two sides

$\huge{Solution}$

Let ABC be the required isosceles triangle with base BC = 5/3 cm

$\mathcal{Now\: we\: know\: that}$

$<b>An isosceles triangle has 2 sides equal</b>$

So, let the two equal sides, i.e. AB and AC be 'x' cm

Now, Perimeter is the sum of all sides.

Hence,

Perimeter = BC + AB+ CA

=> 5/3 + x + x = 43/6

=> x + x = 43/6 - 5/3

=> 2x = 43-10/6

=> 2x = 33/6

=> x = 33/6×2

=> x = 33/12

Hence,

AB = x = 33/12 cm
AC = x = 33/12 cm

$\mathcal{Hence, \:the\: two\: equal\: sides\: \\of \: the \: triangle\: are\:-}$
$\bold{\mathcal{\red{33/12\: cm}}}$

Answer 2

Answer:11/4 cm

I hope this may help u