Question

The base of an isosceles triangle is 8 c.m. If perimeter of the triangle is 20 c.m. , then what is the length of either of the equal sides.​

Answer 1

✬ Equal sides = 6 cm ✬

Step-by-step explanation:

Given:

• Measure of base of isosceles triangle is 8 cm
• Perimeter of isoceles triangle is 20 cm

To Find:

• What is length of the equal sides of ∆?

Solution: Let the length of each sides of isoceles triangle be x cm.

As we know that

★ Perimeter of ∆ = Sum of all sides ★

A/q

• Perimeter = 20 cm

$\implies{\rm }$ 20 = 8 + x + x

$\implies{\rm }$ 20 = 8 + 2x

$\implies{\rm }$ 20 – 8 = 2x

$\implies{\rm }$ 12 = 2x

$\implies{\rm }$ 12/2 = x

$\implies{\rm }$ 6 = x

So,

➟ Length of first equal side is x = 6 cm

➟ Length of 2nd equal side is x = 6 cm

Answer 2

Given ,

• Base of isosceles triangle = 8 cm
• Perimeter of isosceles triangle = 20 cm

Let ,

The measures of equal sides of isosceles triangle be " x "

We know that , the perimeter of triangle is given by

$\large \sf \fbox{Perimeter = A + B + C}$

Thus ,

20 = 8 + x + x

2x = 12

x = 6

$\therefore \sf \underline{The \: length \: of \: either \: of \: the \: equal \: sides \: is \: 6 \: cm </p><p>}$