the bases of two triangles are equal and their corresponding hights are 4cm and 6cm. what is the ratio of areas of these triangles
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Answer:
Let A
1
and A
2
be the areas of the two triangles respectively.
A
1
>A
2
A
1
=
2
1
b
1
h
1
and A
2
=
2
1
b
2
h
2
A
2
A
1
=
2
1
b
2
h
2
2
1
b
1
h
1
5
6
=
b
2
h
2
b
1
h
1
Given that b
1
=b
2
⇒
h
2
h
1
=
5
6
Given h
1
=9cm
⇒
h
2
9
=
5
6
⇒h
2
=
6
9×5
=
6
45
=7.5cm
thus, height of the smaller triangle=7.5cm
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