the brakes applied to a car produce a negative acceleration of 10m/s to the power 2 If the car takes 5 s to stop after applying the brakes calculate the distance covered by the car before coming to rest
krishna67:
what is power 2
write the full question...
it means 10m/s2
Answers
Answered by
54
HI there !
Initial velocity = u
Final velocity = v = 0
acceleration = a = -10 m/s² [ retardation ]
Time = t = 5 sec
Equation of motion :-
v = u + at
0 = u + -10 × 5
0 = u + [-50]
u = 50 m/s
s = distance covered by the car before coming to rest
Equation of motion :-
s = ut + 1/2 at²
= 50 × 5 + 1/2 × -10 × 5 × 5
= 125 metres
Initial velocity = u
Final velocity = v = 0
acceleration = a = -10 m/s² [ retardation ]
Time = t = 5 sec
Equation of motion :-
v = u + at
0 = u + -10 × 5
0 = u + [-50]
u = 50 m/s
s = distance covered by the car before coming to rest
Equation of motion :-
s = ut + 1/2 at²
= 50 × 5 + 1/2 × -10 × 5 × 5
= 125 metres
thank you very much
:)
Answered by
8
Answer:
hi
Explanation:
Initial velocity = u
Final velocity = v = 0
acceleration = a = -10 m/s² [ retardation ]
Time = t = 5 sec
Equation of motion :-
v = u + at
0 = u + -10 × 5
0 = u + [-50]
u = 50 m/s
s = distance covered by the car before coming to rest
Equation of motion :-
s = ut + 1/2 at²
= 50 × 5 + 1/2 × -10 × 5 × 5
= 125 metres
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