the brakes applied to a car produce an acceleration of 6m/s2 in opposite direction to the motion . if the car takes 3sec to come to rest after the application of brakes,calculate the distance covered by the car before stopping
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a=-6m/s
t=3 sec
v=0
s=?
to find s we hv to find u first
using first eq of motion
v=u+at
0=u + (-6)(3)
u=18
now using 2nd eq of motion
s=ut+1/2at^2
s=(18)(3) +1/2*-6*9
s=54-27
s=27
answer =27
hope it helped
t=3 sec
v=0
s=?
to find s we hv to find u first
using first eq of motion
v=u+at
0=u + (-6)(3)
u=18
now using 2nd eq of motion
s=ut+1/2at^2
s=(18)(3) +1/2*-6*9
s=54-27
s=27
answer =27
hope it helped
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