Question

The bus is initially traveling at the velocity of 70km/h. Then breakes are applied then it's velocity decreased to 50km/h. If the declarationis 2m/s×s. Calculate the time

Answer 1

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GiveN :

• Initial velocity (u) = 70 km/h = 19.4 m/s
• Final velocity (v) = 50 km/h = 13.9 m/s
• Acceleration (a) = -2 m/s²

To FinD :

• Time Taken by the bus to decelerate the speed

SolutioN :

Use 1st equation of motion :

$\large{\boxed{\boxed{\sf{v \: = \: u \: + \: at}}}} \\ \\ \implies {\sf{13.9 \: = \: 19.4 \: + \: (-2)t}} \\ \\ \implies {\sf{-2t \: = \: 13.9 \: - \: 19.4}} \\ \\ \implies {\sf{-2t \: = \: -5.5}} \\ \\ \implies {\sf{t \: = \: \dfrac{-5.5}{-2}}} \\ \\ \implies {\sf{t \: = \: 2.75}} \\ \\ \underline{\sf{\therefore \: Time \: taken \: to \: stop \: bus \: is \: 2.75 \: s}}$

Answer 2

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