Math, asked by muhammadhaider4746, 1 year ago

The capacity of a closed cylindrical vessel of height 1m is 15.4 litres. How many square metres of an metal sheet would be needed to make it?

Answers

Answered by Panzer786
27
Hii friend,

HEIGHT OF CYLINDER = 1m

VOLUME OF CYLINDER = 15.4 L = 15400 m³

π²h = 15400

22/7× r² × 1 = 15400

r² = 4900

r = ✓4900 = 70

METALLIC SHEET USED FOR MAKING THE CYLINDER = CSA OF CYLINDER + AREA OF BOTTOM = 2πrh + πr² = πr(2h+r) = 22/7×70(2×1+70) = 220×72 = 15840 M²

HOPE IT WILL HELP YOU.... :-)
Answered by Anonymous
71

\Large{\textbf{\underline{\underline{According\:to\:the\:Question}}}}

Assumption

{\boxed{\sf\:{Radius\;of\;Cylinderical\;vessel=r}}}

Height (h)

= 1m

\textbf{\underline{Convert\;it\;into\;cm}}

[1m = 100 cm]

= 100 cm

Also,

Volume = 15.4 litre

Convert it into cm³

= 15.4 × 10³ cm³

Now,

Volume of Cylinder = πr²h

\tt{\rightarrow 15.4\times 10^3=\dfrac{22}{7}\times r^2\times 100}

\tt{\rightarrow r^2=\dfrac{15.4\times 10^3\times 7}{22\times 10^2}}

\tt{\rightarrow\dfrac{15.4\times 10\times 7}{22}}

\tt{\rightarrow\dfrac{154\times 7}{22}}

= 7 × 7

= 7²

{\boxed{\sf\:{Area\;of\;sheet\;required}}}

= CSA of Cylinder + Area of both circular end

= 2πrh + 2πr²

= 2πr(h + r)

\tt{\rightarrow 2\times\dfrac{22}{7}\times 7(100+7)}

= 44 × 107

= 4708 cm²

Convert it into m²

\tt{\rightarrow\dfrac{4708}{100\times 100m^2}}

= 0.4708 m²

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