Question

The centre of circle is (2alpha-1,7) and it passes through point (-3,-1) if the diameter of circle is 20 units find the value of alpha

Answer 1

equations of circle = >
r^2 = ( x-2alpha+1)^2 + (y-7)^2
diameter = 20
so radius = 20/2 = 10
10^2 = (x-2 alpha +1)^2 + ( y-7)^2
circle is passing through ( -3,-1)
so
100 = ( -3-2alpha+1)^2 + (-1-7)^2
100 = (-2-2alpha)^2 + 64
36 = ( -2-2alpha )^2
6 = -2-2alpha
8 = -2 alpha
alpha = - 4

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Answer 2

Answer:

Step-by-step explanation:

equations of circle = >

r^2 = ( x-2alpha+1)^2 + (y-7)^2

diameter = 20

so radius = 20/2 = 10

10^2 = (x-2 alpha +1)^2 + ( y-7)^2

circle is passing through ( -3,-1)

so

100 = ( -3-2alpha+1)^2 + (-1-7)^2

100 = (-2-2alpha)^2 + 64

36 = ( -2-2alpha )^2

6 = -2-2alpha

8 = -2 alpha

alpha = - 4

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