Math, asked by niladrisekhar19, 1 year ago

The chocolate factory is preparing a delivery of Valentine's chocolate boxes. In a single container they can fit eight large chocolate boxes or ten small chocolate boxes. They send ninety-six chocolate boxes in one day using more large boxes than small ones. How many containers did they use?

Answers

Answered by gilapokemonp3y1rg
83
Easy
it's logical but mathematically hard to explain
8x7=56 (big boxes)
96-56=40
10x4=40 (small boxes)
56+40=96
since big boxes are are more than small boxes
number of boxes 7+4=11 containers
Answered by hotelcalifornia
0

Answer:

11 containers are used to send those 96 chocolate boxes.

To find:

Number of containers used

Solution:

Given

1 container = 8 large boxes or 10 small boxes.  

Now, let us check the different situations of sending 96 chocolate boxes as under:

1. If only large boxes are used to send 96 chocolates boxes, then

\begin{array} { c } { \frac { \text {Total no. of chocolate boxes} } { \text {No. of large boxes fit in } 1 \text { container } } } \\\\ { = \frac { 96 } { 8 } } \end{array}

= 12 large boxes

But small boxes are also used and number of large boxes are more than small ones.

2. Considering both small and large boxes for sending 96 boxes, we can have this:

No. of large  No. of small Total boxes send

boxes used  boxes used  

12 x 8 = 96            -                       96  (using only large ones)

11 x 8 = 88           **                       88  (**min. 10 is needed)

10 x 8 = 80     1 x 10 = 10              90  

9 x 8 = 72      2 x 10 = 20             92  

8 x 8 =64       3 x 10 = 30             94    

7 x 8 =56      4 x 10 = 40             96

Hence total number of containers = 7 + 4 = 11 containers

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