Question

The chord of a circle of radius 10 cm substends a right angle at its centre. Find the length of the chord

Answer 1

Take a right angle triangle BOC,

      BC2 = OB2 + OC2

=> BC2 = (10)2 + (10)2

=> BC2 = 100 + 100

=> BC2 = 200

=> BC = √200

=> BC = √(100*2)

=> BC = 10√2

So, the length of the chord is 10√2 cm