the circumference of circle exceeds its diameter by 18 cm find radius
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Hey mate..
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Let, the circumference of a circle be 2πr ( °•° r is the radius of a circle )
A/Q,
=> 2πr = d + 18
=> πd = d + 18 ( °•° 2r = d )
=> πd - d = 18
=> d ( π - 1 ) = 18
=> d ( 22/7 - 1 ) = 18
=> d ( 22 - 7 / 7 ) = 18
=> 15d / 7 = 18
=> d = 18 × 7 / 15
=> d = 8.4 cm
=> r = 8.4 / 2 cm
=> r = 4.2 cm
Thus, The radius of the circle is 4.2 cm
Hope it helps !!
========
Let, the circumference of a circle be 2πr ( °•° r is the radius of a circle )
A/Q,
=> 2πr = d + 18
=> πd = d + 18 ( °•° 2r = d )
=> πd - d = 18
=> d ( π - 1 ) = 18
=> d ( 22/7 - 1 ) = 18
=> d ( 22 - 7 / 7 ) = 18
=> 15d / 7 = 18
=> d = 18 × 7 / 15
=> d = 8.4 cm
=> r = 8.4 / 2 cm
=> r = 4.2 cm
Thus, The radius of the circle is 4.2 cm
Hope it helps !!
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