Question

the class room door is of width 50 cm. If the handle of door is 20 CM from the edge and the force of 20 N is applied on the handle. Find the torque​

Answer 1

Answer:

4 NM

Explanation:

So we will convert the cm to meter therefore the Handle length will become 0.2 meters.

Now the moment of force or torque will be:

Force * perpendicular distance

= 20*0.2

= 4NM