Question

the coach of a cricket team buys 3 bats and 6 balls for Rs. 3900. later, she buys another bat and 3 balls of same kind for Rs. 1300. Represent this situation algebraically and geometrically.
.
.
.
.
.
Don't Spam...​

Answer 1

let rate of bat = xRs.

and rate of ball = yRs.

3x+6y=3900...(i)

and x+3y=1300...(ii)

or x=(1300−3y)

now equation (i) can be written as

3(1300−3y)+6y=3900

3900−9y+6y=3900

∴y=0

Ans:- x=1300

Answer 2

Answer:

let rate of bat = x

let rate of ball = y

3x + 6y = 3900 (i)

x + 3y = 1300 (ii)

x = (1300 - 3y)

3(1300 - 3y) + 6y = 3900

:. y = 0

:. x = 1300

Step by step explaination:

Hope this helps you unnie, do you remember me? I'm your Pikachu. i hope you're safe. Take care unnie :)