the coefficients of restitution for a perfectly elastic collision is
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e=1 for
perfectly elastic
perfectly elastic
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The coefficient of restitution for collisions can be calculated from the velocity of separation (i.e. relative speed after the collision) divided by the velocity of approach (closing speed if you like)
In a 'perfectly elastic' collision these two quantities will be equal. The simplest example might be a moving pool ball hitting a stationary one head on. The first ball stops and the second one moves off at the same speed that the first one was moving. Hence the velocity of separation is the same as the velocity of approach and the collision is perfectly elastic (in a simple model anyway). The kinetic energy is conserved.
In perfectly inelastic collision the velocity of separation is zero. It might seem possible to get rid of all kinetic energy (as opposed to conserving it), but this is not the case, as the total momentum of a system must always be conserved. So the most inelastic collisions possible are when the two objects stick together.
In a 'perfectly elastic' collision these two quantities will be equal. The simplest example might be a moving pool ball hitting a stationary one head on. The first ball stops and the second one moves off at the same speed that the first one was moving. Hence the velocity of separation is the same as the velocity of approach and the collision is perfectly elastic (in a simple model anyway). The kinetic energy is conserved.
In perfectly inelastic collision the velocity of separation is zero. It might seem possible to get rid of all kinetic energy (as opposed to conserving it), but this is not the case, as the total momentum of a system must always be conserved. So the most inelastic collisions possible are when the two objects stick together.
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