Question

The combustion of ethanol, C2H5OH(l), in oxygen to form carbon dioxide gas and water vapor is shown by which balanced chemical equation?
A) C2H5OH(l) + O2(g) → CO2(g) + H2O(g)
B) C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(g)
C) 2CO2(g) + 3O2(g) → C2H5OH(l) + 3H2O(g)
D) 2CO2(g) + 3H2O(g) → C2H5OH(l) + 3O2(g)

Answer 1

Explanation:

B) OPTION IS CORRECT ANSWER

Answer 2

Answer:

B

Explanation:

C2H5OH(l) + O2(g) → CO2(g) + H2O(g)  

balance ur carbon first by adding 2 to CO2 so that there is 2Cc on each side of the equation

C2H5OH(l) + O2(g) → 2CO2(g) + H2O(g)

now your Hydrogen, theres 6H on the reaction side and 2H on H2O so add 3 to h2o to make it 6H in total

C2H5OH(l) + O2(g) → 2CO2(g) + 3H2O(g)

now count your Oxygens. theres [ 1+2 ] = 3O on the reaction side and [ (2x2) + (3x1)] = 7O on the product side. Now in order to balance that you can add 3 to O2 to make it 6O + the 1O on the C2H5OH to make it 7O

= C2H5OH(l) + 3O2(g) → 2CO2(g) + H2O(g