Question

the compound interest in 6 years is 4000 and compound interest of same sum in 12 years become 9600 then find the sum?​

Answer 1

$\huge\boxed{\underline{\red{\fcolorbox{red}{pink}{Answer}}}}$

$\mathbf{\underline{given}}$

• compound interest in 6 years = 4000
• compound interest in 12 year = 9600
• Find the sum of money

$\mathbf{\underline{formula = p < 1 + i > {}^{2} }}$

$\mathbf{\underline{solution}}$

• p[(1+i)⁶] = 4000+p i
• p[(1+i)¹²] = 9600+p ..ii
• divide

$\mathbf{\underline{so , result is (1+i)⁶=9600+p/4000+p </p><p>}}$

• ☞put this value in 1st equation.. calculation is attached..

• ☆ the answer is p = 10000 ( sum of money )

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