Question

the compound interest on ₹10000 at 10% pa for 3 years compounded annually​

Answer 1

Answer: 3000.

Step-by-step explanation:

Compound interest is given as

CI = ptr/100.

P =10000.

T = 3 years.

R = 10%.

CI = 10000*10*3/ 100.

= 300000/100.

= 3000.

Answer 2

GIVEN :-

• Principal (P) = ₹ 10000
• Rate ( R %) = 10 % P.A
• Time (t) = 3 years.

TO FIND :-

• The compound interest .

SOLUTION :-

➠ Here find the compound interest let's find the amount first , Now apply the formula of amount

$\implies \boxed{ \boxed{ \red{ \bf \: \:Amount = p \bigg \{1 + \dfrac{R }{100} \bigg \} ^{n} }}}$

➠ Now substitute the values,

$\to \rm \: 10000 \bigg \{1 + \dfrac{10}{100} \bigg \} ^{3} \\ \\ \to \rm \: 10000 \bigg \{ \dfrac{1 \times 100}{100} + \dfrac{10}{100 } \bigg \} ^{3} \\ \\ \to \rm \: 10000 \bigg \{ \dfrac{100 + 10}{100} \bigg \}^{3} \\ \\ \to \rm \: 10000 \bigg \{ \frac{ \cancel{110}}{ \cancel{100}} \bigg \} ^{3} \\ \\ \to \rm \: 10000 \bigg \{ \dfrac{11}{10} \bigg \} ^{3} \\ \\ \to \rm \: 10 \: \cancel{000} \bigg \{ \dfrac{1331}{ \cancel{1000}} \bigg \} \\ \\ \to \rm \: 10 \times 1331 \\ \\ \to \boxed{ \red{ \rm13310}}$

➠ Hence got the amount = ₹ 13310

➠ Now let's apply the formula for compound interest,

$\to \boxed{ \boxed{ \red{ \bf \:C.I = Amount - Pricipal }}} \\ \\ \to \rm \: 13310 - 10000 \\ \\ \to \rm \red{3310}$

Hence the compound interest is ₹ 3310