Question

the compound interest on 4000 at 10% per annum for 2 years 3 months compound annually will be​

Answer 1

Answer:

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We will first calculate the compound interest on ₹ 4000 for 2 years at 10% per annum.

P = ₹4000 , R = 10%, n= 2 years

Amount  = Principal (1 + R/100)ⁿ

A = 4000 ( 1+10/100)²

A = 4000 × (110/100)²

A = 4000 × 110/100 × 110/100

A = 40 × 11 × 11

Amount =  ₹4840

Thus the amount at the end of 2 years is ₹4840.This will be the principal for the remaining 3 months (3/12) which is 1/4 years.

P = ₹4840 for T = 1/4 year at R = 10% p.a

Simple interest I = P×R×T

                                  100  

I = 4840 × 10× 1

         100   ×  4    

Interest = ₹121

Thus the amount at the end of 2 1/4 years = ₹(4840 + 121) = ₹4961

Thus the compound interest = Amount - CI  

CI = ₹(4961 - 4000)

CI = ₹961

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HOPE IT HELPS!!!

Answer 2

Principal(P) = Rs 4000

Rate of Interest(r ) = 10%

Time = 2 years and 3 months

Here first we take n = 2 years.

A = P( 1 + r /100)n Where A = Amount and n = number of years

A = 4000 (11/10)2

A = 4000 ( 121 / 100 )

A = Rs 4840

The Amount after two years = Rs 4840

Now Principal = Rs 4840

Simple interest for last 3 month i.e 1/4 year is = PRT/100 = (4840 × 10 × 1 / 4) / 100 = Rs.121

Amount after 2 years and 3 months = Rs 4840 + Rs 121 = Rs 4961

C.I = A - P

C.I = 4961 - 4000 = Rs. 961

∴ The compound interest is Rs. 961