Math, asked by Sindhudevi3517, 11 months ago

The compound interest on rs 10 @ 10% per annum for two years will be
The compound interest on rupees 10 @ 10% per annum for 2 years will be

Answers

Answered by arvindkakade
8
compound interest after 2yrs of 1000 Rs at the rate 10% per annum is 210 Rs.
it is given that principal , P = 1000 Rs.
rate of interest , r = 10% per annum
time duration, n = 2 yrs
using formula, C.I = P[(1 + r/100)ⁿ - 1]
= 1000[(1 + 10/100)² - 1]
= 1000[(1 + 1/10)² - 1]
= 1000[(1 + 0.1)² - 1]
= 1000[(1.1)² - 1]
= 1000[1.21 - 1]
= 1000 × 0.21
= 210 Rs.
hence, compound interest = 210 Rs.
Answered by Devisha08
0

Answer:

Step-by-step explanation:

Principle= Rs.10

Rate= 10%

Time=2 Years

C.I= Amount- principal

And amount= Principal (1+R/100)^T

So, Initially, we will insert values

             10(1+10/100)²

Then, we will change 10/100 in its standard form i.e- 1/10

             10( 1+1/10)²

After that, we will take LCM of 1 and 1/10

           10(11/10)²

Then, we will square 11/10 and multiply it by 10

              10X121/100

               =12.1

So, our amount will be equal to 12.1

                    to take out C.I, we will put the formula

                                      Amount-Principal

                                           12.1-10 =2.1

                                      ∴  C.I= 2.1      

                   

             

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