The compound interest on rs 10 @ 10% per annum for two years will be
The compound interest on rupees 10 @ 10% per annum for 2 years will be
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compound interest after 2yrs of 1000 Rs at the rate 10% per annum is 210 Rs.
it is given that principal , P = 1000 Rs.
rate of interest , r = 10% per annum
time duration, n = 2 yrs
using formula, C.I = P[(1 + r/100)ⁿ - 1]
= 1000[(1 + 10/100)² - 1]
= 1000[(1 + 1/10)² - 1]
= 1000[(1 + 0.1)² - 1]
= 1000[(1.1)² - 1]
= 1000[1.21 - 1]
= 1000 × 0.21
= 210 Rs.
hence, compound interest = 210 Rs.
it is given that principal , P = 1000 Rs.
rate of interest , r = 10% per annum
time duration, n = 2 yrs
using formula, C.I = P[(1 + r/100)ⁿ - 1]
= 1000[(1 + 10/100)² - 1]
= 1000[(1 + 1/10)² - 1]
= 1000[(1 + 0.1)² - 1]
= 1000[(1.1)² - 1]
= 1000[1.21 - 1]
= 1000 × 0.21
= 210 Rs.
hence, compound interest = 210 Rs.
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0
Answer:
Step-by-step explanation:
Principle= Rs.10
Rate= 10%
Time=2 Years
C.I= Amount- principal
And amount= Principal (1+R/100)^T
So, Initially, we will insert values
10(1+10/100)²
Then, we will change 10/100 in its standard form i.e- 1/10
10( 1+1/10)²
After that, we will take LCM of 1 and 1/10
10(11/10)²
Then, we will square 11/10 and multiply it by 10
10X121/100
=12.1
So, our amount will be equal to 12.1
to take out C.I, we will put the formula
Amount-Principal
12.1-10 =2.1
∴ C.I= 2.1
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