Question

The coordinates of point P and Q are 4,-3 and -1,7 respectively. Find the abscissa of a point R on a line segment PQ such that PR/PQ=3/5
Please give the solution urgently. Tomorrow is my exam...

Answer 1

Answer :

P .___R__.Q

Given that, PR/PQ = 3/5

Here, RQ = PQ - PR = 5 - 3 = 2

So, the point R divides the segment PQ in the ratio 3 : 2 internally.

(4, -3) P.___R__.Q (-1, 7)

So, the co-ordinates of the point P be

( (2×4 - 3×1)/(3+2), (-3×2 + 3×7)/(3+2) )

i.e., ( (8-3)/5, (-6+21)/5 )

i.e., (5/5, 15/5)

i.e., (1, 3)

So, the coordinates of R is (1, 3)

Hence, the abscissa of the point R is 1

#MarkAsBrainliest

Answer 2

PR/PQ = 3/5 [given]
So, RQ
= PQ - PR
= 5 - 3
= 2

That means the point R divides the segment PQ in the ratio 3 : 2.

co-ordinates of point P[(2×4 - 3×1)/(3+2), (-3×2 + 3×7)/(3+2) ]=[ (8-3)/5, (-6+21)/5 ]
=[5/5, 15/5]=[1, 3]
Coordinates of R
= [1, 3]
So, the abscissa of the point R is = 1