Question

The coordinates of the vertices of triangleABC are A(4,1) , B(3,-2) and C(0,k) if area of triangle ABC is 12 sq units find the value of k

Answer 1

Area=1/2|4(-2 - k) +3(k-1)+0|=12
-8-4k+3k-3=24
-k=35
K=-35

Answer 2

Answer:

13/-7

1/2 ∫ x1 (y2 - y1) + x2(y3 - y1) + x3 ( y1 - y2) ∫

↑this is the area of triangle formula and ∫ resembles the absolute value.