The correct formula to calculate the percentage of water imbided by raisins
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atkah23:
No i wanted 1st bt
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We can calculate %age of water by
W1=4.0 g. Let W2 be the weight of raisins after immersing in water for few hours.W2=7.0 g. Therefore, the weight of water absorbed by raisins is W2-W.W2-W1=3.0 g. The percentage of water absorbed by raisins = [(W2-W1)/W1]*100% [(W2-W1)/W1]*100% =75 %
W1=4.0 g. Let W2 be the weight of raisins after immersing in water for few hours.W2=7.0 g. Therefore, the weight of water absorbed by raisins is W2-W.W2-W1=3.0 g. The percentage of water absorbed by raisins = [(W2-W1)/W1]*100% [(W2-W1)/W1]*100% =75 %
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