Chemistry, asked by Niwwen2784, 11 months ago

The correct order of increasing bond angles in the following
triatomic species is :
(a) NO₂⁻ < NO₂⁺ < NO₂ (b) NO₂⁻ < NO₂ < NO₂⁺
(c) NO₂⁺ < NO₂ < NO₂⁻ (d) NO₂⁺ < NO₂⁻ < NO₂

Answers

Answered by shainazsangam
0

Answer:

According to VSEPR theory, The order of repulsion of electrons is lp-lp repulsion gt lp-bp repulsion gt bp-bp repulsion Higher the number of lone pair of electrons (greater is repulsion ) lower is the bond angle and vice-versa. In NO−2 one lone pair of electron is present while in NO+2 no lone pair of electron is present. Hence the correct order of bond angles is NO−2<NO2<NO+2

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