Question

The correct sequence which shows decreasing order of the ionic radii of the element is (a) O2– > F– > Na+ > Mg2+ > Al3+ (b) Al3+ > Mg2+ > Na+ > F– > O2– (c) Na+ > Mg2+ > Al3+ > O2– > F– (d) Na+ > F– > Mg2+ > O2– > Al3+

Answer 1

Answer:

All the given species are isoelectronic. Among isoelectronic species anions generally have greater size than cations. Also greater the nuclear charge Z of the ion smaller the size. Thus the order is : O2– > F– > Na+ > Mg2+ > Al3+

Answer 2

Answer:

The correct sequence which shows decreasing order of the ionic radii of the element is,  $O^{2-} > F^{-} > Na{+} > Mg^{2+} > Al^{3+}$

Explanation:

The species are isoelectronic i.e., which has same number of  electrons.

All the compounds has full filled octoate electronic configuration or they

are isoelectronic species.

Again, for isoelectronic species, r∝ $\frac{1}{Z}$

Where,

r is the ionic radii,

Z is the effective nuclear charge.

Hence, Larger the atomic number i.e., effective nuclear charge smaller will be the ionic radii.

Al has the atomic number 13, similarly Mg has the atomic number 12, Na has the atomic number 10 and F has the atomic number 9 and O has the atomic  number 8.

So, correct sequence which shows decreasing order of radii is, option(A)$O^{2-} > F^{-} > Na{+} > Mg^{2+} > Al^{3+}$.

To know more about isoelectronic species, follow the link given below,

https://brainly.in/question/118329

To know more about this answer, follow the link given below,

https://brainly.in/question/15417894

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