Math, asked by 1234kash, 1 year ago

the cost of a machine depreciated by 4000 during the first year and by 3600 during the second year calculate
(1) the rate of depreciation
(2) the original cost of the machine
(3) its cost at the end of the third year

Answers

Answered by mathupto12
24
1.10%
2.40000
3.40000-4000-3600-3240
=29160

mathupto12: I also said its 10%
1234kash: you write 1.10%
mathupto12: I wrote that ans of 1st is 10%
1234kash: ohh sorry
1234kash: but answer did not matching
1234kash: ohh sorry
1234kash: can you send me the full procces
1234kash: please its urgent i really need it
anju133: can you send me the full procces
1234kash: can you explain the full procces
Answered by ssonalishrma710
198

1) depreciated money of 1st year-2nd year= 4000-3600=400

R=I×100/P×T

R=400×100/4000×1 =10%

Therefore rate of depreciation =10%

2) depreciated price of the 1st year=4000

P=I×100/R×T

P=4000×100/10×1 =40000

Therefore orignal cost=40000

3) 1st year A=40000-4000= 36000

2nd year A= 36000-3600=32400

For 3rd year I=P×R×T/100

32400×10×1/100 =3240

A= 32400-3240 (besause of depreciation)

A= 29160

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