the cost of a machine depreciated by 4000 during the first year and by 3600 during the second year calculate
(1) the rate of depreciation
(2) the original cost of the machine
(3) its cost at the end of the third year
Answers
Answered by
24
1.10%
2.40000
3.40000-4000-3600-3240
=29160
2.40000
3.40000-4000-3600-3240
=29160
mathupto12:
I also said its 10%
Answered by
198
1) depreciated money of 1st year-2nd year= 4000-3600=400
R=I×100/P×T
R=400×100/4000×1 =10%
Therefore rate of depreciation =10%
2) depreciated price of the 1st year=4000
P=I×100/R×T
P=4000×100/10×1 =40000
Therefore orignal cost=40000
3) 1st year A=40000-4000= 36000
2nd year A= 36000-3600=32400
For 3rd year I=P×R×T/100
32400×10×1/100 =3240
A= 32400-3240 (besause of depreciation)
A= 29160
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