The cost of cultivating a circular field at the rate of 2.25 per acre (1 acre = 100 sq m) is Rs346.50. Find the cost of fencing it with a wire costing rs3.50 per metre.
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Answer:
346.50/2.25
= 154 acre
15400 m²
let radius be x
(22× x²)/7 =15400
x²=4900
x=70m
so circumference = length of wire need for fencing
(2×7×22)/7
=44m
1 m cost = ₹3.50
so 44 m cost = 3.50×44
= ₹154 is the cost of fencing the field
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Therefore cultivating 1m
Therefore cultivating 1m 2
Therefore cultivating 1m 2 cost Rs.
Therefore cultivating 1m 2 cost Rs. 100
Therefore cultivating 1m 2 cost Rs. 1002.25
Therefore cultivating 1m 2 cost Rs. 1002.25
Therefore cultivating 1m 2 cost Rs. 1002.25
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2
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Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2 Then ,1002.25
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2 Then ,1002.25 ×x=346.50
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2 Then ,1002.25 ×x=346.50225x=3465000
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2 Then ,1002.25 ×x=346.50225x=3465000x=15400 m
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2 Then ,1002.25 ×x=346.50225x=3465000x=15400 m 2
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2 Then ,1002.25 ×x=346.50225x=3465000x=15400 m 2
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2 Then ,1002.25 ×x=346.50225x=3465000x=15400 m 2 Therefore we can say that,
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2 Then ,1002.25 ×x=346.50225x=3465000x=15400 m 2 Therefore we can say that, πr
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2 Then ,1002.25 ×x=346.50225x=3465000x=15400 m 2 Therefore we can say that, πr 2
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2 Then ,1002.25 ×x=346.50225x=3465000x=15400 m 2 Therefore we can say that, πr 2 =15400
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2 Then ,1002.25 ×x=346.50225x=3465000x=15400 m 2 Therefore we can say that, πr 2 =15400r
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2 Then ,1002.25 ×x=346.50225x=3465000x=15400 m 2 Therefore we can say that, πr 2 =15400r 2
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2 Then ,1002.25 ×x=346.50225x=3465000x=15400 m 2 Therefore we can say that, πr 2 =15400r 2 =4900
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2 Then ,1002.25 ×x=346.50225x=3465000x=15400 m 2 Therefore we can say that, πr 2 =15400r 2 =4900r=70 m
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2 Then ,1002.25 ×x=346.50225x=3465000x=15400 m 2 Therefore we can say that, πr 2 =15400r 2 =4900r=70 mAnd perimeter =2πr=2×
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2 Then ,1002.25 ×x=346.50225x=3465000x=15400 m 2 Therefore we can say that, πr 2 =15400r 2 =4900r=70 mAnd perimeter =2πr=2× 7
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2 Then ,1002.25 ×x=346.50225x=3465000x=15400 m 2 Therefore we can say that, πr 2 =15400r 2 =4900r=70 mAnd perimeter =2πr=2× 722
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2 Then ,1002.25 ×x=346.50225x=3465000x=15400 m 2 Therefore we can say that, πr 2 =15400r 2 =4900r=70 mAnd perimeter =2πr=2× 722
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2 Then ,1002.25 ×x=346.50225x=3465000x=15400 m 2 Therefore we can say that, πr 2 =15400r 2 =4900r=70 mAnd perimeter =2πr=2× 722 ×70=440 m
Therefore cultivating 1m 2 cost Rs. 1002.25 Let area which was cultivated be x m 2 Then ,1002.25 ×x=346.50225x=3465000x=15400 m 2 Therefore we can say that, πr 2 =15400r 2 =4900r=70 mAnd perimeter =2πr=2× 722 ×70=440 mHence cost of fencing at Rs.1.20 per m=440×1.20=Rs.528