Math, asked by lokamsaisupriya2000, 6 months ago

The cost of diamond varies directly as the square of its weight Once
this diamond broke into four pieces with weights in the ratio 1:2:3:4
When the pieces were sold, the merchant got Rs 70,000 less. Find the
original price of the diamond​

Answers

Answered by sibhiamar
1

Answer:

original price of the diamond = 1,00,000

Step-by-step explanation:

diamond broke into four pieces with weights in the ratio 1:2:3:4

so original weight of unbroken diamond is 1x + 2x + 3x + 4x = 10x

so original price of unbroken diamond is (10x)^2 * y = 100x^2 * y........(1)

y is certain rate of diamond

total price all broken diamond = [(1x)^2 + (2x)^2 + (3x)^2 + (4x)^2] * y = 30x^2 * y

lost money = 100x^2 * y - 30x^2 * y = 70x^2 * y

70,000 = 70x^2 * y

1000 = x^2 * y sub in (1)

100(x^2 * y )= 100 * 1000 = 100,000

Answered by 2006ujjwal07
0

Answer:

be confidential I couldn't see anything

Similar questions