Question

the cost of diamond varies directly as the square of its weight a diamond weighting 10 decigrams costs rs.8000 if it break into two pieces whose weight are in ratio 3:2 then the loss incurred is​

Answer 1

Let we are taking (k) as non zero constant

weight of diamond (w) = 10 gms

cost of diamond( c)= rs 8000

c varies x^2

or,c / x^2=k

or,8000/(10*10)= k

or,k =80

again, the diamond was broken in ratio=3:2 and let the broken part be A and B respectively

or,sum of ratio=3+2

=5

or, mass of A=(3/5)*10

=6 gms

or, mass of B =(2/5)*10

=4 gms

or, cost of A is C`

C`= k*d^2

=80*(6*6)

= rs 2880 ans

cost of B is c`

c`=k*d^2

=80*(4*4)

= rs 1280 ans

Answer 2

Step-by-step explanation:

we have to add to the above ans. that is

Cost of (A+B)=Rs. (2880+1280)

=Rs. 4160

therefore,

Loss incurred = Rs. (8000-4160)

= Rs.3840