Question

the digit at tens place of a two digit number is 4 times the digit at units place if the sum of this number and the number formed by reversing the digits is 55 find the number ​

Answer 1

Let the digit at one's place be x.

The digit at ten's place=4x

Therefore, the two digit number=10(4x) +x=40x+x=41x

On reversing the number,the digit at one's place =x

And the digit at ten's place=4x

So, the two digit no.=10(x)+4x

=10x+4x=14x

=According to the question,

=41x+14x=55

=55x=55

=x=55/55

=x=1

The two digit number=41x=41*1=41

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Answer 2

Step-by-step explanation:

1. summary.
2. ride
3. drills
4. collapse
5. IQ
6. grow
7. Rossi
8. selfish

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