The cost of planting grass in a circular park at the rate of Rs 4.90/m2 is Rs 24, 640. A path of uniform width runs around the park. The cost of gravelling the path at the rate of rs 3.50/m2is Rs 3696.
1) Find the cost of fencing the path on both sides at the rate of Rs 2.10/m.
soon please
Answers
Answered by
11
⭕️Let radius of the circular park be r m.
⭕️Area of circular park = πr2
⭕️Cost of planting grass in 1 m2 = Rs 4.90
∴Rs 4.90 x πr2 = Rs 24640
r^2= 24640 x 7 ÷ 4.90 x 22
simplifying;
r= 40
⭕️So the radius of park will be 40m
⭕️ width of the path be x m.
⭕️Area of the path = π [(40 + x)2 – (40)2]
∴ 3.50 × π [(40 + x)2 – (40)2 ] = 3696
simplifying;
⇒ x2 + 80x – 336 = 0
⇒ x2 + 84x – 4x – 336 = 0
⇒ x (x + 84) – 4(x + 84) = 0
⇒(x + 84)( x –4)= 0
⇒ x + 84 = 0 or x –4 = 0
⇒ x = – 84 or x = 4
⇒ x = 4
Width of the park = 4 m
⭕️Length of the wire to fence the path on both sides = Circumference of the inner circle+Circumference of outer circle
➖️Circumference of the inner circle
= 2π × 40 cm = 80π m
➖Circumference of outer circle
= 2π × 44 cm = 88π m
➖Length of the wire needed to fence the path on both sides
= (80π+ 88π) m = 168π m.
➖Cost of fencing 1 m = ₹2.10
∴Cost of fencing 168π m = Rs 2.10 × 168π = ₹ 1108.80
✔️✔️the cost of fencing the path on both sides is /= 1108.80
⭕️Area of circular park = πr2
⭕️Cost of planting grass in 1 m2 = Rs 4.90
∴Rs 4.90 x πr2 = Rs 24640
r^2= 24640 x 7 ÷ 4.90 x 22
simplifying;
r= 40
⭕️So the radius of park will be 40m
⭕️ width of the path be x m.
⭕️Area of the path = π [(40 + x)2 – (40)2]
∴ 3.50 × π [(40 + x)2 – (40)2 ] = 3696
simplifying;
⇒ x2 + 80x – 336 = 0
⇒ x2 + 84x – 4x – 336 = 0
⇒ x (x + 84) – 4(x + 84) = 0
⇒(x + 84)( x –4)= 0
⇒ x + 84 = 0 or x –4 = 0
⇒ x = – 84 or x = 4
⇒ x = 4
Width of the park = 4 m
⭕️Length of the wire to fence the path on both sides = Circumference of the inner circle+Circumference of outer circle
➖️Circumference of the inner circle
= 2π × 40 cm = 80π m
➖Circumference of outer circle
= 2π × 44 cm = 88π m
➖Length of the wire needed to fence the path on both sides
= (80π+ 88π) m = 168π m.
➖Cost of fencing 1 m = ₹2.10
∴Cost of fencing 168π m = Rs 2.10 × 168π = ₹ 1108.80
✔️✔️the cost of fencing the path on both sides is /= 1108.80
Answered by
7
Heyy mate ❤✌✌❤
Here's your Answer....
⤵️⤵️⤵️⤵️⤵️⤵️⤵️
Let the radius of the circular park be r m.
Area of the circular park = πr2
Cost of planting grass in 1 m2 = Rs 4.90
∴Rs 4.90 × πr2 = Rs 24640
=> r^2 = 24640 × 7/ 4.90 × 22
=> r^2 = 1600
=> r = 40m.
Let the width of the path be x m.
Area of the path = π [(40 + x)2 – (40)2]
∴ Rs 3.50 × π [(40 + x)2 – (40)2 ] = Rs 3696
=> 1600 + 80x + x^2 -1600 = 3696 × 7/ 22 × 3.50. = 336
=> x^2 + 80x – 336 = 0
⇒ x^2 + 84x – 4x – 336 = 0
⇒ x (x + 84) – 4(x + 84) = 0
⇒(x + 84)( x –4)= 0
⇒ x + 84 = 0 or x –4 = 0
⇒ x = – 84 or x = 4
⇒ x = 4
Width of the park = 4 m
Now,
Length of the wire needed to fence the path on both sides = Circumference of the inner circle + Circumference of outer circle
=> Circumference of the inner circle = 2π × 40 cm = 80π m
Circumference of outer circle = 2π × 44 cm = 88π m
Length of the wire needed to fence the path on both sides = (80π+ 88π) m = 168π m.
Now,
Cost of fencing 1 m = Rs 2.10
∴Cost of fencing 168π m = Rs 2.10 × 168π = Rs 1108.80
✔✔✔
Here's your Answer....
⤵️⤵️⤵️⤵️⤵️⤵️⤵️
Let the radius of the circular park be r m.
Area of the circular park = πr2
Cost of planting grass in 1 m2 = Rs 4.90
∴Rs 4.90 × πr2 = Rs 24640
=> r^2 = 24640 × 7/ 4.90 × 22
=> r^2 = 1600
=> r = 40m.
Let the width of the path be x m.
Area of the path = π [(40 + x)2 – (40)2]
∴ Rs 3.50 × π [(40 + x)2 – (40)2 ] = Rs 3696
=> 1600 + 80x + x^2 -1600 = 3696 × 7/ 22 × 3.50. = 336
=> x^2 + 80x – 336 = 0
⇒ x^2 + 84x – 4x – 336 = 0
⇒ x (x + 84) – 4(x + 84) = 0
⇒(x + 84)( x –4)= 0
⇒ x + 84 = 0 or x –4 = 0
⇒ x = – 84 or x = 4
⇒ x = 4
Width of the park = 4 m
Now,
Length of the wire needed to fence the path on both sides = Circumference of the inner circle + Circumference of outer circle
=> Circumference of the inner circle = 2π × 40 cm = 80π m
Circumference of outer circle = 2π × 44 cm = 88π m
Length of the wire needed to fence the path on both sides = (80π+ 88π) m = 168π m.
Now,
Cost of fencing 1 m = Rs 2.10
∴Cost of fencing 168π m = Rs 2.10 × 168π = Rs 1108.80
✔✔✔
Similar questions
Computer Science,
7 months ago
History,
1 year ago