the current in a conductor varies with time t s is equals to 2T + 3 square I is in ampere and t is and second electric charge flowing through a section of conducted during t is equals to 2 second 2 t is equals to 3 second is
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The current flowing through the conductor is 24 coulomb.
Explanation:
From question,
I = 2t + 3t²
dQ/dt = 2t + 3t²
The current from 2 seconds to 3 seconds is:
Q = ∫dQ/dt =
Q = [2t²/2 + 3t³/3]³₂
Q = [t² + t³]³₂
On applying the limits, we get,
Q = (9 + 27) - (4 + 8)
Q = 36 - 12
∴ Q = 24 coulomb
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