Question

the curve has an equation of y= 4x^3-3x+3.
find the coordinates of 2 stationary points

Answer 1

Answer:

x=$x=\frac{1}{2},-\frac{1}{2}$

Step-by-step explanation:

given

$y=4x^3-3x+3$

now

$12x^2-3=0 \implies 4x^2-1=0\\\implies x^2=\frac{1}{4}\implies x=\frac{1}{2} ,-\frac{1}{2}}$