Question

the curved surface area of conical tent is 550 sq.m and area of its base is 154 sq.m and find the volume of the air inside the tent

Answer 1

$\pi \: {r}^{2} = 154 \: {m}^{2} \\ {r}^{2} = \frac{154 \times 7}{22} = 7 \times 7 \\ r = 7 \: m \\ \pi \: r \: l = 550 {m}^{2} \\ l = \frac{550 \times 7}{22 \times 7} = 25m \\ {h}^{2} = {l}^{2} - {r}^{2} = 625 - 49 = 576 \\ h = 24 \\ volume \: of \: air = \pi \: {r}^{2} h = \frac{22}{7} \times 7 \times 7 \times 24 \\ = 3696 {m}^{3}$