Question

The decomposition of N₂O₅ is represented by the equation
2N₂O₅ (g) → 4NO₂ (g) + O₂ (g)
How is the rate of formation of NO₂ related to the rate of formation of O₂?

Answer 1

N₂O₅ --> 4 NO₂ + O₂  

The stoichiometry of the composed reaction assurances that  

for small finite time intervals, rate = –(½)(d[N₂O₅]/dt) .. or –(½)(∆[N₂O₅]/∆t)  

for small finite time intervals, rate = +(¼)(d[NO₂]/dt) .. or –(½)(∆[NO₂]/∆t)  

for small finite time intervals, rate = +(d[O₂]/dt) .. or –(½)(∆[O₂]/∆t)  

The answer will be positive to all.