Question

the density of 2.03 m solution of acetic acid is 1.017 g per ml. calculate the molarity of the solution​

Answer 1

Answer:

No. Of moles =2.03mol

Molar mass of acetic acid =60g/mol

Density 1.017g/ml

Molarity =?

Sol;

Given mass of acetic acid=n ×molar mass

=2.03×60=121.8g

Volume =mass given /density

V=121.8/1.017

=119ml

Molarity =n×1000/volume

=2.03 × 1000/119

=17.05ml=17.05cm^3

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